Besar sudut CED = A. 50° B. 60° C. 70° D. 75°

180 = (4x+4) + (3x+8) + (5x)
180 = 12x + 12
168 = 12x
x = 14

CED = 3(14) + 8 = 50° (A)

180° = (4x + 4°) + (3x + 8°) + (5x)
180° - 4° - 8° = 4x + 3x + 5x
168° = 12x
168°/12 = x
14° = x

<CED = 3x + 8°
= 3(14) + 8
= 50°
jadi, jawabannya adalah A. 50°