hasil dari integral tak tentu

misal u = 3x - 2
du = 3dx
dx = du/3
u = 3x - 2
3x = u + 2
x = (u+2)/3
4x = (4/3)(u+2)
jadi kita jadiakan u dulu disoalnya
(4/3)(u+2) u³ du/3
nah du/3 kita pindah per 3nya kedepan
(4/9) (u + 2) u³ du
u³ kita kalika ke (u + 2)
(4/9) (u⁴ + 2u³) du
baru diintegral kan
(4/9) {1/(4+1) u^(4+1) + 2/(3+1) u^(3+1)} + C
(4/9) {(1/5)u^5 + (2/4)u^4} + C
(4/9) {(1/10)u^4(2u + 5)} + C
(4/9 × 1/10) u^4(2u + 5) + C
(4/90) u^4(2u + 5) + C
masukan u = 3x - 2
(2/45)(3x - 2)⁴(2(3x-2) + 5) + C
(2/45)(3x - 2)⁴(6x - 4 + 5) + C
(2/45) (3x - 2)⁴ (6x + 1) + C
atau bisa disesuaikan dengan pilihan
(2/45) (1 + 6x) (3x - 2)² + C