Matematika

Pertanyaan

Integral cos4x sin2x dx

1 Jawaban

  • Int (cos 4x sin 2x) dx
    = Int 1/2 . (2 cos 4x sin 2x) dx
    = Int 1/2 (sin (4x + 2x) - sin (4x - 2x)) dx
    = Int (1/2 sin 6x - 1/2 sin 2x) dx
    = 1/2 . -1/6 cos 6x - 1/2 . -1/2 cos 2x + C
    = -1/12 cos 6x + 1/4 cos 2x + C

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