Jika f(x) = -2x+4/x-6; x ¥ 6, maka f^-1(x) =

jika gini → f(x) = (-2x + 4)/(x - 6)
bisa pake rumus,ato bertahap
y = (-2x + 4)/(x - 6)
y(x + 6) = -2x + 4
xy + 6y = -2x + 4
xy + 2x = 4 - 6y
x(y + 2) = 4 - 6y
x = (4 - 6y)/(y + 2)
invers gnti y dengan x
f^-1(x) = (4 - 6x)/(x + 2)

(-2x + 4)/(x - 6) = y
xy - 6y = -2x + 4
xy + 2x = 6y + 4
x(y + 2) = 6y + 4
x = (6y + 4)/(y + 2)
f^-1(x) = (6x + 4)/(x + 2) ; x ≠ -2

Atau jika f(x) = (ax + b)/(cx + d) => f^-1(x) = (-dx + b)/(cx - a)
f(x) = (-2x + 4)/(x - 6) => f^-1(x) = (6x + 4)/(x + 2) ; x ≠ -2

x + 2 ≠ 0 => x ≠ -2