Matematika

Pertanyaan

5 log 3=a dan 3log 2=b nilai 6log 125 daoat dinyatakan

2 Jawaban

  • ^5 log 3=a
    ^3 log 2=b
    ^6 log 125=?

    ^6 log 125=(^3 log 125)/(^3 log 6)
    =(^3 log 5³)/(^3 log (2×3))
    =3(^3 log 5)/(^3 log 2 + ^3 log 3)
    =3(1/a)/(b+1)
    =3/(a(b+1)
    =3/(ab+a)
  • 6 log 125 = 3 ³log 5 per ³ log 2 + 1 = 3(b+1) per a

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