tolong bantu ya kak:)

1)  JWB A
lim(x->0)  (3 - 3cos 2x) / (5 tan² 3x)
= lim(x->0)  3 (1- cos 2x) / (5. tan² 3x)
= lim(x->0)  3 (2 sin²  x) / (5. tan² 3x)
= 6/5 . (1²)/(3²)
= (6/5)(1/9) = 6/45
= 2/15

2)
₋₁¹∫ x⁴/³ + 4 x¹/³ dx = [ ³/₇ x⁷/³ + 3 x⁴/³ ]¹₋₁
 = ³/₇ ∛x⁷ + 3 ∛x⁴ ]¹₋₁
= ³/₇ {1-(-1)} + 3{1 -1}
= ³/₇ (2) + 0
= ⁶/₇