Matematika

Pertanyaan

limit x-> 1
x²-1/x-1 + x²+3x+2/x²-4x+3
mohon dengan penjelasannya

1 Jawaban

  • penyelesaian

    Limit x --> 1
    ( (x² - 1) / (x - 1) ) + ( (x² + 3x + 2) / (x² - 4x + 3) )

    = Limit x --> 1
    ( ( (x - 1) (x + 1) ) / (x -1) ) + ( (x² + 3x + 2) / ( (x - 3) (x - 1) ) )

    = Limit x --> 1
    ( (x + 1) / (x - 1) ) + ( (x² + 3x + 2) / ( (x - 3) (x - 1) ) )

    = Limit x --> 1
    ( (x + 1) (x - 3) / (x - 1) (x - 3) ) + ( (x² + 3x + 2) / ( (x - 3) (x - 1) ) )

    = Limit x --> 1
    ( (x² - 2x -3) / (x - 3) (x - 1) ) + ( (x² + 3x + 2) / ( (x - 3) (x - 1) ) )

    = Limit x --> 1
    (x² - 2x -3) + (x² + 3x + 2) / ( (x - 3) (x - 1) )

    = Limit x --> 1
    (2x² +x -1) / (x² - 4x + 3)

    = (2(1)² +(1) -1) / ( (1)² - 4(1) + 3)
    = 2 / 0
    = ∞

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