Matematika, soalnya ada di gambar

1) √3 - Tan 2x = 0
Tan 2x = √3
Tan 2x = Tan 60°
2x = 60° + k . 180°
x = 30° + k . 90°
x = 30° => untuk k = 0
x = 120° => untuk k = 1
x = 210° => untuk k = 2
x = 300° => untuk k = 3
x = 390° (Tdk Memenuhi) => untuk k = 4
HP = {30°, 120°, 210°, 300°}

2) √3 Tan x = - 1
Tan x = -1/√3
Tan x = (-1/3)√3
Tan x = Tan 150° => kuadran 2
Tan x = Tan 330° => kuadran 4
HP = {150°, 330°}

3) cos x = -1/2 √2
Cos x = cos 135° => kuadran 2
Cos x = cos 225° => kuadran 3
HP = {135°, 225°}

4) 1 + √2 sin x = 0
√2 sin x = -1
Sin x = -1/√2 = -1/2 √2
Sin x = sin 225° => kuadran 3
Sin x = sin 315° => kuadran 4
HP = {225°, 315°}

5) 2 cos x = 1
Cos x = 1/2
Cos x = cos 60° => kuadran 1
Cos x = cos 300° => kuadran 4
HP = {60°, 300°}

6) 2 sin x - √3 = 0
2 sin x = √3
Sin x = 1/2 √3
Sin x = sin 60° => kuadran 1
Sin x = sin 120° => kuadran 2
HP = {60°, 120°}