Persamaan garis singgung pada kurva y = √x + 1/√x + 1 x√x di titik (1,3) adalah...

dy/dx = 1/(2√x) - 1/(2(x^(3/2)) + (3√x)/2
dy/dx(1) = 1/2 - 1/2 + 3/2 = 3/2

y = x•dy/dx + C
3 = 1(3/2) + C
C = 3/2

y = 3x/2 + 3/2
2y = 3x + 3