Matematika

Pertanyaan

a) Sec²x(1-cos²x)=tan²x
b) secx-cosx=sinx.tanx

Sama caranya yaa bantuin Please:v

1 Jawaban

  • a) sec^2 x (1 - cos^2 x)
    = [1/(cos^2 x] (sin^2 x)
    = (sin^2 x)/(cos^2 x)
    = Tan^2 x

    b) sec x - cos x
    = (1/(cos x)) - cos x
    = (1 - cos^2 x)/(cos x)
    = (sin^2 x)/(cos x)
    = sin x . (sin x)/(cos x)
    = sin x Tan x

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