Jika diketahui a=16, b=27/8 dan c=125, maka nilai [a^3/4+b^-2/3 : c^2/3]^-1 adalah...

a=16=2^4
b=27/8=3^3/2^3=3/2^3
c=125=5^3
Berarti:
(2^3×4/4+3/2^3×-2/3+5^3×2/3)^-1
=2^-3+3/2^2+5^-2
=1/8+9/4+1/25
Disamakan
25+450+8/200=483/200

a=16, b=27/8 dan c=125, maka nilai [a^3/4+b^-2/3 : c^2/3]^-1 =
Maka = 2^4 ,b =( 3/2)^3 dan c = 5^3
[2^4×3/4 + (3/2)^3×-2/3 : 5^3×2/3 ]^-1
[2^3 + (3/2)-2 × 5^-2]^-1
1/8 + 9/4 × 25
1/8 + 225/4 = 451/8