Deret geometri 243 + 81 + 27 + 9 + 3 + . . . ., jumlah 10 suku pertama adalah . . . .?

Bab Pola Bilangan

a = 243
r = 81/243 = 1/3

Sn = (a(1 - r^n))/(1 - r)
S10 = (243(1 - 1/3^10))/(1 - 1/3)
S10 = (243(1 - 1/59.049))/(2/3)
S10 = (243(59.048/59.049)) × 3/2
S10 = (59.048/243) × 3/2
S10 = 29.524/81
S10 = 364 40/81