6log216 + √2log16 x 4log32 : 3log54 - 3log2

Bab Logaritma

⁶log 216 + √²log 16 × ⁴log 32 : ³log 54 - ³log 2
= 3 + 8 × ⁵/₂ : ³log (⁵⁴/₂)
= 3 + 20 : ³log 27
= 3 + 20 : 3
= 3 ²⁰/₃
= 9 ²/₃

(6log216 + √2log16 . 4log32) / (3log54 - 3log2)
= (6log6^3 + 2^1/2log2^4 . 2^2log2^5) / (3log(54/2))
= (3 . 6log6 + 4/(1/2) . 2log2 . 5/2 . 2log2) / (3log27)
= (3 + 8 . 5/2) / (3log3^3)
= (3 + 20) / (3 . 3log3)
= 23/3
= 7 2/3