hasil dari integral (7-3x)pangkat5 dx=

int (7 - 3x)^5 dx
u = 7 - 3x
du = -3 dx
dx = -(1/3) du
= -(1/3) int u^5 du
= -(1/18)u^6 + c
= -(1/18)(7 - 3x)^6 + c

integral ( 7 - 3x)^5 dx
u = 7 - 3x
du = -3 dx
dx = -(1/3) du
= -(1/3) int u^5 du
= -(1/18) u^6 + c
= -(1/18) (7 -3x)^6 + c