Jika f(x) = 1/ (x^2 + x +4)^3 maka nilai 16f'(-1) =....
Matematika
Kharisma99
Pertanyaan
Jika f(x) = 1/ (x^2 + x +4)^3 maka nilai 16f'(-1) =....
1 Jawaban
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1. Jawaban Anonyme
f(x) = (x² + x + 4)^-3
f'(x) = -3(x² + x + 4)^-4.(2x + 1) = -3(2x + 1)/(x² + x + 4)^4
16f'(-1) = 16[-3(-2 + 1)/(1 + 1 + 4)] = 8