Hasil ari integral 6x(25-5)^3=... A. -3/20 (8x+5)(2x-5)^4+C B. -3/40 (8x+5)(2x-5)^4+C C. 3/40 (8x+5)(2x-5)^4+C D. 3/40 (5x+8)(2x-5)^4+C E. 3/20 (5x+8)(2x-5)^4+C

6x(2x - 5)³ dx gitu yah mestinya
u = 2x - 5
du = 2dx
dx = du/2
u = 2x - 5
2x = u + 5
6x = 3(u + 5) = 3u + 15
ganti dengan u
(3u + 15) u³ du/2
per dua pindahin ke depan
(1/2) (3u⁴ + 15u³) du
(1/2) {(3/5)u^5 + (15/4)u^4)} + C
(1/2) {(3/20)u^4 (4u + 25)} + C
ganti u
(1/2)(3/20) (2x - 5)⁴(4(2x-5) + 25) + C
(3/40) (2x - 5)⁴ (8x - 20 + 25) + C
(3/40) (8x + 5) (2x - 5)⁴ + C