tentukan persamaan garis singgung pada lingkaran (x+2)² + (y-1)² = 25 di titik (-6,4)

(x + 2)² + (y - 1)² = 25
(x + 2)(-6 + 2) + (y - 1)(4 - 1) = 25
-4(x + 2) + 3(y - 1) = 25
-4x - 8 + 3y - 3 = 25
-4x + 3y - 11 = 25
-4x + 3y - 36 = 0
------------------------ (× -1)
4x - 3y + 36 = 0

pusat lingkaran = (-2,1)—>(a,b)
r=5
titik (-6,4)—>(x1,y1)

PGS
(x1-a)(x-a)+(y1-b)(x-b)=r²
(-6+2)(x+2)+(4-1)(x-1)=25
-4x-8+3y-3-25=0
3y-4x-36=0

cmiiw