Tentukan panjang vektor c yang diwakili oleh ruas garis berarah AB jika A(3, -2) dan B(-1, 2).

|C| = AB

AB = B - A
= (-1, 2) - (3, -2) = (-4, 0)

|AB| = |C| maka,

|C| = akar [(-4)^2 + (0)^2]

|C| = akar 16 = 4

AB = b - a = (-1,2) - (3, -2) = (-4, 4)
|c| = |AB| = √((-4)^2 + 4^2) = √(16 + 16) = √32 = 4√2