Matematika

Pertanyaan

Tolong dibantu jawab
Tolong dibantu jawab

2 Jawaban

  • Pake sifat limit fungsi trigonometri

    caranya saya tulis dikertas .
    #CMIIW
    Gambar lampiran jawaban hardzal
  • 6) Lim (6x + 2 sin 4x) / (3x + Tan 2x) ............. . (1/x)/(1/x)
    = Lim (6x/x + 2 (sin 4x)/x) / (3x/x + (Tan 2x)/x)
    = (6 + 2(4)) / (3 + 2)
    = 14/5

    7) Lim (sin 3x (1 - cos 2x))/(2x^3)
    = Lim (sin 3x . 2 sin^2 x) / (2x^3)
    = Lim (sin 3x . sin x . sin x)/(x^3)
    = Lim (sin 3x)/x . (sin x)/x . (sin x)/x
    = 3 . 1. 1
    = 3