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Matematika
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2 Jawaban
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1. Jawaban hardzal
Pake sifat limit fungsi trigonometri
caranya saya tulis dikertas .
#CMIIW2. Jawaban arsetpopeye
6) Lim (6x + 2 sin 4x) / (3x + Tan 2x) ............. . (1/x)/(1/x)
= Lim (6x/x + 2 (sin 4x)/x) / (3x/x + (Tan 2x)/x)
= (6 + 2(4)) / (3 + 2)
= 14/5
7) Lim (sin 3x (1 - cos 2x))/(2x^3)
= Lim (sin 3x . 2 sin^2 x) / (2x^3)
= Lim (sin 3x . sin x . sin x)/(x^3)
= Lim (sin 3x)/x . (sin x)/x . (sin x)/x
= 3 . 1. 1
= 3Pertanyaan Lainnya