Matematika

Pertanyaan

Sin A . Cos A (tan A + cotan A)

2 Jawaban

  • = Sin A . Cos A (SinA/CosA + CosA/SinA)
    = SinA . Cos A (Sin^2A/SinACosA + Cos^2A/ SinACosA)

    = SinA . CosA . Sin^2 A + Cos^2 A / SinA.CosA
    = Sin^2 A + Cos^2 A
  • = sin a . cos a ( Tan a + cotan a )
    = sin a . cos a ( Tan a + 1/tan a)
    = sin a . cos a ( sin/cos a + cos/sin a )
    = sin²a + cos²a

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