tolong dong..............

[(2log8 + 2log3 . √3log4)/(3log2 - 3log18)]^2
= [(2log2^3 + 2log3 . 3^1/2log2^2) / (3log(2/18)) ]^2
= [(3 . 2log2 + 2log3 . 2/(1/2) . 3log2) / (3log1/9) ]^2
= [(3 + 4 . 2log3 . 3log2)/(3log3^-2)]^2
= [(3 + 4)/-2)]^2
= (7/-2)^2
= 49/4