diketahui 60 gr NO ( ar N =14, O = 16). ditanya a. mol NO = ? b. jumlah molekul gas c. volume NO jika pada temperatur tertentu = 10L SO3 = 16 gr ( ar S = 33,O

Massa NO = 60 gr

Mr NO = Ar N + Ar O
Mr NO = 14 + 16
Mr NO = 30

n NO = massa / Mr
n NO = 60 gr / 30
n NO = 2 mol

NA = 6,02 × 10²³

Jmlh molekul = n × NA
Jmlh molekul = 2 mol × 6,02 × 10²³
Jmlh molekul = 1,204 × 10²⁴ molekul

Mr SO3 = Ar S + 3 Ar O
Mr SO3 = 32 + 3(16)
Mr SO3 = 80

n SO3 = massa SO3 / Mr SO3
n SO3 = 16 gr / 80
n SO3 = 0,2 mol

V SO3 = 10 L

n NO / V NO = n SO3 / V SO3
2 mol / V NO = 0,2 mol / 10 L
V NO = 100 L