Titik balik/puncak dari fungsi kuadrat f (x) = x2 – 6x + 8 adalah ....

f(x) = x^2 - 6x + 8
x = -b/2a = -(-6)/2(1) = 6/2 = 3
y = f(3) = 3^2 - 6(3) + 8 = 9 - 18 + 8 = -1
Titik balik = (3, -1)