jika f'(x) menyatakan turunan pertama dari f(x) dan f(x) = 2x³- 1/ x³+2 ,nilai dari f'(2) =..... a. 1/20 b. 1/10 c. 1/2 d.3/5 e. 4/5

Turunan

f(x) = (2x³-1) /(x³+2)
u = 2x³-1 --> u' = 6x²
v = x³ + 2 --> v' = 3x²

f(x)= u/v --> f'(x)= (u'v - uv') / (v²)

f'(x) = { 6x²(x³+2) - (2x³-1)(3x²)} / (x³ +2)²
f'(x)= { 6x⁵+12x² -( 6x⁵-3x²)} / (x³+2)²
f'(x) = (6x⁵+12x² -6x⁵ + 3x²) / (x³+2)²
f'(x)= (15 x²)/(x³+2)²
f'(2) = (15.2²)/ (2³+2)² = (15)(4)/ (10)² =60/100
f'(2) = 3/5