Fisika

Pertanyaan

2x-6 per x+3 + 6 per x-3 =

2 Jawaban

  • 2x-6/x+3 + 6/x-3
    = (2x²-12x+18)+(6x+18)/x²-9
    = 2x²-12x+6x+18+18/x²-9
    = 2x²-6x+36/x²-9

  • tanpa tanda kurung, perhitungan mengikuti aturan urutan operasi

    2x-6 / x+3 + 6 / x-3
    = 2x - 6/x + 3 + 6/x - 3
    = 2x ← jawaban

    cek
    http://m.wolframalpha.com/input/?i=2x-6+%2F+x%2B3+%2B+6+%2F+x-3&x=8&y=8

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