tolong bantu jawab pake caranya yaaa

²log(x - 2√2) + ²log(x + 2√2) < 0
²log(x - 2√2)(x + 2√2) < ²log1 -------->> (coret ²log)
(x - 2√2)(x + 2√2) < 1
x² - 8 < 1
x² - 8 - 1 < 0
x² - 9 < 0
(x - 3)(x + 3) < 0
x = 3 V x = -3
( - 3 < x < 3)

Syarat pembatas:
x - 2√2 > 0 atau x + 2√2 > 0
x > 2√2 atau x > - 2√2

(-3 < x < 3) ∩ (x > 2√2) ∩ (x > - 2√2) 

Hp = {2√2 < x < 3}