diketahui f(x)= 2xakar2 + 3x - 5 dan g(x)= 3x -2 agar (gof) (a)= -11 maka nilai a adalah.... mohon caranya juga yaa

Fungsi Komposisi

f(x) = 2 x√2 + 3x - 5
g(x) = 3x - 2

gof(a) = -11
g{ f(x)}= -11
g {2 a√2 + 3a - 5) = -11
3 {2 a√2 + 3a - 5) -2 =-11
3 ( 2 a√2 + 3a - 5) = -11+ 2  = -9
2a√2 + 3a - 5 = -9/3 = - 3
2a √2 + 3a = -3 + 5 = 2
2√2 a + 3a = 2
a (2√2 + 3) = 2
a = 2 / (2√2 + 3)
a = 2(2√2 - 3)/ (8-9)
a = (4√2 - 6)/ (-1)
a = 6 - 4√2