diketahui luas permukaan balok 736 cm2 panjang balok 16 cm dan lebar 10 cm. volume balok tersebut adalah

Lp = 2 (pl + pt + lt)
736 = 2 (16.10 + 16 . t + 10 . t)
736 = 2 (160 + 16t + 10t)
736 = 2 (160 + 26t)
736 = 320 + 52t
52t = 736 - 320
52t = 216
t = 216 / 54
t = 4

V = p x l x t
V = 16 x 10 x 4
V = 16 x 40
V = 640

Luas permukaan = 2(pl + pt + lt)
736 = 2((16 × 10) + (16 × t) + (10 × t)
736 = 2(160 + 16t + 10t)
736 = 2(160 + 26t)
736 = 320 + 52t
736 - 320 = 52t
416 = 52t
t = 416/52
t = 8 cm

Volume = p × l × t
= 16 × 10 × 8
= 1.280 cm³