Barisan geometri suku ke2 adl 4/3 dan suku ke5 adalah 36 maka suku ke 6 ?

U2 = ar = 4/3
U5 = ar^4 = 36

U5 : U2 = 36 : 4/3
ar^4 / ar = 36 (3/4)
r^3 = 27
r = 3

ar = 4/3
a.3 = 4/3
a = 4/3 : 3
a = 4/9

U6 = ar^5
U6 = 4/9 (3^5)
U6 = 4/3² (3^5)
U6 = (4) . (3^3)
U6 = 4 x 27
U6 = 108

Bab Baris dan Deret
Matematika SMP Kelas IX


U2 = 4/3
a.r = 4/3

U5 = 36
a.r^4 = 36

a.r = 4/3
a.r^4 = 36
r^-3 = 1/27
1/r^3 = 1/27
r^3 = 27
r = 3.

a.r =4/3
3a=4/3
a = 4/3/3
a = 4/3 x 1/3
a = 4/9.

U6 = ?
U6 = a.r^5
= 4/9 . 3^5
= 4/9 . 243
= 4x27
= 108

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