diketahui f(x)=4x-7.nilai f(3m+1)+f(2)adalah

Pembahasan.

Hitung dulu f(3m + 1) dan f(2) .

Rumus umum = 4x - 7

f(3m + 1) = 4(3m + 1) - 7
f(3m + 1) = 12m - 3

f(2) = 4(2) - 7
f(2) = 8 - 7
f(2) = 1

f(3m + 1) + f(2) = 12m - 3 + 1
f(3m + 1) + f(2) = 12m - 2

f(3m+1)=4(3m+1)-7=12m+4-7=12m-3
f(2)=4(2)-7=8-7=1
f(3m+1)+f(2)=12m-3+1=12m-2