Bantu tentukan bilangan oksidasi Dari undue digambar

d). (2 x (+3)) + (3 x C) + (9 x (-2) = 0
(+6) + (3 x C) + (-18) = 0
3 × C = +12
biloks C = -4

e). (3 × (+1) + As + (3 × (-2)) =0
(+3) + (As) +(-6) = 0
As - 3 = 0
biloks As= +3

f). (+1) + Cl + (3 × (-2)) = 0
(+1) + Cl + (-6) = 0
Cl - 5 = 0
biloks Cl = +5

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