Limit x->0 (1-cos 8x)/(sin 2x Tan 2x)
Matematika
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Pertanyaan
Limit x->0 (1-cos 8x)/(sin 2x Tan 2x)
1 Jawaban
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1. Jawaban abyandaffa11
cos 8x = 1 - 2 sin^2 4x
1 - (1 - 2 sin^2 4x) / sin 2x tan 2x
= 2 sin 4x . sin 4x / sin 2x tan 2x
= 2 × 4 × 4 / 2 × 2
= 8