persamaan garis yg melalui titik (-2,4) dan tegak lurus dengan garis yg melalui titik (-5,6) dan (9,-1) ? dibantu ya kak

y2-y1 : x2-x1
-1 -6 :9 - (-5)
-7 :14
m = -2
tegak lurus = m1.m2 = -1
-2 . m2 = -1
m2 = -1 / -2 = 1/2

y-y1 = m(x-x1)
y-4 = 1/2 (x-(-2)
y-4 = 1/2 (x+2)
2(y-4) = 1(x+2)
2y -8 = x + 2
2y -x = 2 -(-8)
2y - x = 10
2y - x -10 = 0

[tex]y2-y1 : x2-x1 -1 -6 :9 - (-5) -7 :14 m = -2 tegak lurus = m1.m2 = -1 -2 . m2 = -1 m2 = -1 / -2 = 1/2 y-y1 = m(x-x1) y-4 = 1/2 (x-(-2) y-4 = 1/2 (x+2) 2(y-4) = 1(x+2) 2y -8 = x + 2 2y -x = 2 -(-8) 2y - x = 10 2y - x -10 = 0[/tex]