integral x√2x+5 dx tolong bantuin jawab yaa

jika gini → int x√(2x + 5) dx
u = 2x + 5 → du = 2 dx
dx = (1/2) du
L = (1/2) int x√u du
dari u = 2x + 5
2x = u - 5
x = (1/2)(u - 5)
L = (1/2)(1/2) int (u - 5)√u du
= (1/4) int (u^(3/2) - 5u^(1/2)) du
= (1/4)[(2/5)u^(5/2) - (10/3)u^(3/2)] + c
= (1/4)[(2/5)√(2x + 5)^5 - (10/3)√(2x + 5)] + c
tinggal sederhanakan, misal
= (1/15)(2x + 5)(3x - 5)√(2x + 5) + c
atau bntuk lain...