Terdapat 100 mL larutan CaF2 0,1 M yang akan diukur pH-nya. Jika Ka HF = 3,4 × 10^-4, maka tentukan harga Kh dan pH larutan garam tersebut berserta caranya

Kh = Kw / Ka
Kh = 10⁻¹⁴/3,4.10⁻⁴
Kh = 0,294.10⁻¹⁰
Kh = 2,94.10⁻¹¹

[H+] = √Kh . M . valensi
[H+] = √2,94.10⁻¹¹.10⁻¹.2
[H+] = √5,88.10⁻¹²
[H+] = 2,42.10⁻⁶

pH = - log 2,42.10⁻⁶
pH = 6 - log 2,42
pH = 5,61