Tolong dibantu ya 3x +5y ≥ 15, 7x + 4y ≤ 28, y ≥ 0, x ≥ 0
Matematika
gayatritiara
Pertanyaan
Tolong dibantu ya
3x +5y ≥ 15, 7x + 4y ≤ 28, y ≥ 0, x ≥ 0
3x +5y ≥ 15, 7x + 4y ≤ 28, y ≥ 0, x ≥ 0
1 Jawaban
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1. Jawaban Lismayaningsih
3x + 5y > 15
mis x = 0
3(0) + 5y = 15
0 + 5y = 15
5y = 15
y = 15/5
y = 3
mis y = 0
3x + 5(0) = 15
3x = 15
x = 15/3
x = 5
7x + 4y < 28
mis x = 0
7(0) + 4y = 28
4y = 28
y = 28/4
y = 7
mis y = 0
7x + 4(0) = 28
7x = 28
x = 28/7
y = 4