Matematika

Pertanyaan

Tolong dibantu ya
3x +5y ≥ 15, 7x + 4y ≤ 28, y ≥ 0, x ≥ 0

1 Jawaban

  • 3x + 5y > 15
    mis x = 0
    3(0) + 5y = 15
    0 + 5y = 15
    5y = 15
    y = 15/5
    y = 3

    mis y = 0
    3x + 5(0) = 15
    3x = 15
    x = 15/3
    x = 5

    7x + 4y < 28
    mis x = 0
    7(0) + 4y = 28
    4y = 28
    y = 28/4
    y = 7

    mis y = 0
    7x + 4(0) = 28
    7x = 28
    x = 28/7
    y = 4

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