Sebanyak 0,37 gram Ca(OH) dilarutkan dalam air hingga volume 250 ml.jikaAr:Ca=40,O=16,H=1,tentukanhargaPHdan pOH?

mol Ca(OH)2 =0,37/74 = 5x10^-3
M= n/v = 5x10^-3/25x10^-2 = 2x10^-6
[OH-] = M x Valensi basa
= (2x10^-6) x 2
= 4x 10^-6
POH = -log 4x10^-6 = 6+log 4
PH = 14-POH
= 14- 6+log 4
= 8+log 4