Matematika

Pertanyaan

suatu fungsi f dinyatakan dengan rumus f(×)=ax+b, jika f(3)=17, dan f(-2)=-3 , maka nilai f(5)adalah

1 Jawaban

  • f(x) = ax + b

    f(3) = a(3) + b = 17
    = 3a + b = 17

    f(-2) = a(-2) + b = -3
    = -2a + b = -3

    jadi (3a + b = 17) - (-2a + b = -3)
    5a = 20
    a = 4
    3a + b = 17
    3(4) + b = 17
    12 + b = 17
    b = 17-12
    b = 5

    f(5) = a(5) + b
    = 4(5) + 5
    = 20 + 5
    = 25


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