tentukan sifat dan ph larutan garam CH3COOK 0,01 M (ka = 10^-5)

CH3COOK 0,01 M
Ka = 10^-5

pH ... ?

CH3COOK = K^{+} + CH3COO^-
.... 0,01 M ... 0,01 M ... 0,01 M

Garam CH3COOK bersifat basa
[OH^-] = √( Kw/Ka × M anion )
[OH^-] = √( 10^-14/10^-5 × 0,01 )
[OH^-] = √( 10^-9 × 0,01 )
[OH^-] = √( 10^-11 )
[OH^-] = 10^-5,5

pOH = - log [OH^-]
pOH = - log 10^-5,5
pOH = 5,5

pH = 14 - pOH
pH = 14 - 5,5
pH = 8,5