Jika diketahui p = 8/125; q = 27; dan r = 32. Maka nilai (q^2/3 + r^2/5 / p^-2/3 )^-1 adalah A. 5/52 B. 25/52 C. 13/25 D. 52/25 E. 68/25
Matematika
Violandawidiatama
Pertanyaan
Jika diketahui p = 8/125; q = 27; dan r = 32. Maka nilai (q^2/3 + r^2/5 / p^-2/3 )^-1 adalah
A. 5/52
B. 25/52
C. 13/25
D. 52/25
E. 68/25
A. 5/52
B. 25/52
C. 13/25
D. 52/25
E. 68/25
1 Jawaban
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1. Jawaban bapakdr
q^2/3 = 27^2/3 = (3^3)^2/3 = 3^(3×2/3) = 3^2 = 9
r^2/5 = 32^2/5 = (2^5)^2/5 = 2^(5×2/5) = 2^2 = 4
p^-2/3 = (8/125)^-2/3 = 8^-2/3 / 5^-2/3
= (2^3)^-2/3 / (5^3)^-2/3
= 2^(3×-2/3) / 5^(3×-2/3)
= 2^-2 / 5^-2
= 5^2 / 2^2
= 25/4
{(9 + 4) / (25/4)}^-1
= (13 / (25/4))^-1
= (13 × 4/25)^-1
= (52/25)^-1
= 25/52