please' tolong dibantu. besok dikumpul, klw bisa yg no. 3 dengan cara jalannya.. thank's :)

lim x→0 [√(x²+x)-√x]/(x√x) =
lim x→0 [√x.(√(x+1)-1]/(x√x) =
lim x→0 [√(x+1)-1]/x =
lim x→0 [√(x+1)-1]/x × (√(x+1)+1)/(√(x+1)+1) =
lim x→0 [(x+1)-1] / [x × (√(x+1)+1) ] =
lim x→0 x / [x(√(x+1) + 1) ] =
lim x→0 1 / [√(x+1) + 1 ] =
==> 1 / [√(0+1) + 1 ] =
1 / [√1 + 1 ] =
1/ (1+1) =
1/2

Jadi, hasilnya 1/2