Integral(5-tan^2 x) dx Its pangkat 2. Bukan2x Tolong all.

Identitas trigonometri :
1 + tan^2 x = sec^2 x => tan^2 x = sec^2 x - 1

Int (sec^2 x) dx = Tan x + C
karena turunan dari Tan x adalah sec^2 x

Jadi
Int (5 - tan^2 x) dx
= Int (5 - (sec^2 x - 1)) dx
= Int (5 - sec^2 x + 1) dx
= Int (6 - sec^2 x) dx
= 6x - Tan x + C