Matematika

Pertanyaan

suatu fungsi f(2x-1)=4x+7
nilai f(5)=
#tolongdibantuyekak

1 Jawaban

  • f(2x-1)=4x+7
    misal
    t = 2x-1
    2x = t+1
    x = t+1 / 2
    f(x) = 4(t+1 / 2) + 7

    f(5)=4(5+1 / 2)+7
    =4(3)+7
    =12+7
    =19

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