suatu fungsi f(2x-1)=4x+7 nilai f(5)= #tolongdibantuyekak
Matematika
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Pertanyaan
suatu fungsi f(2x-1)=4x+7
nilai f(5)=
#tolongdibantuyekak
nilai f(5)=
#tolongdibantuyekak
1 Jawaban
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1. Jawaban EdiHeaven
f(2x-1)=4x+7
misal
t = 2x-1
2x = t+1
x = t+1 / 2
f(x) = 4(t+1 / 2) + 7
f(5)=4(5+1 / 2)+7
=4(3)+7
=12+7
=19